3 ms·

now, i might be wrong, but i managed to simplify it down to: x= exp(k/(k-1)) my math is definitely rusty. be kind. (and i don't have my calculator) edit: as

• apu 19y ago
  I think you might be mistaken...e.g., plugging in k=0 yields x=e, but if you put x=e in the original equation, you get k=e.
• brent 19y ago
  Yes, this is not correct. This would would mean x asymptotically approaches e as k increases. However, if k = 30, x should be nearly 150. See my other post for more details.