4 ms·
Clearest way I see. Is to look at the equivalent form: x^k = e^x. Then aneesh's solutions seem obvious. I don't believe there's an analytic solution either. Ot
by dnaquin 19y ago
Clearest way I see. Is to look at the equivalent form: x^k = e^x. Then aneesh's solutions seem obvious.
I don't believe there's an analytic solution either. Otherwise it'd be in my CRC as x/ln(x) crops up quite a bit.
- Xichekolas 19y agoYeah I got it to the x^k = e^x form, but that is where I got stuck. I was just hoping there was some trick to pull at that point that I couldn't remember, but extensive review of my logarithm/exponent rules was getting me nowhere.