You're right. This seems like a hard problem, esp. since OP is so emphatic that $300 is preferrable to $500. Let me see if I can figgure this out for us both.

You're right. This seems like a hard problem, esp. since OP is so emphatic that $300 is preferrable to $500. Let me see if I can figgure this out for us both. 1 child x $500 = $500 1-or-more x $500 = $500-or-more Oh! That must be it! This solution would be more expensive to implement, and therefore, since cost is a factor, this solution would be less preferable! Glad I took the time to work this one out, I certainly was very confused as well.