3 ms·
Perhaps you can go even further and try to make it so that any two points have pairwise correct distances, like in the Azimuthal equidistant projection? https:
by darkmighty 9y ago
Perhaps you can go even further and try to make it so that any two points have pairwise correct distances, like in the Azimuthal equidistant projection?
https://en.wikipedia.org/wiki/Azimuthal_equidistant_projection https://en.wikipedia.org/wiki/Azimuthal_equidistant_projecti...
Perhaps there are metric functions where this is not possible (a quick proof eludes me...[1]), but approximations might be possible anyway.
[1] Edit: actually it's quite simple. Any non-isotropic metric cannot have an Euclidean equidistant projection, simply take a pair of points lying in rays (1,0) and (0,1) in an L^p metric, p not 2, as a counterexample.
- darkmighty 9y agoEdit2: Forget everything I said :) My geometry is quite rusty I guess. Not only any non-isotropic metric cannot have an Euclidean equidistant projection, any non-Euclidean metric clearly can't have an Euclidean equidistant projection. Metric spaces are defined by pairwise distances! What you can do however, is make the distance to 1 or 2 arbitrarily chosen points correct.