4 ms·
a|b would be the obvious choice, because it already works for set: {1,2}|{2,3} == {1,2,3} I guess the reason they went for the weird {∗∗a, ∗∗b} syntax is
by namelost 9y ago
a|b would be the obvious choice, because it already works for set:
{1,2}|{2,3} == {1,2,3}
I guess the reason they went for the weird {∗∗a, ∗∗b} syntax is that it is not a commutative operation.
- mixmastamyk 9y agoWouldn't mind that either.
- akvadrako 9y agoI guess I didn't explain it clearly enough. ∗∗a is not new syntax, it's just applicable in a new context.