3 ms·

I'm not sure what you mean, since current compilers already warn if you write that code.

• jhg 16y ago
  Hmm, OK. Try a different example - the compiler should allow the following code without any warnings: void foo(int * a) { } void bar(int * b) { foo(b); } void baz(const int * c) { bar(c); } Point being is that the compiler should warn of the const violation based on whether a function argument or a class member is getting touched in the function code. In fact, the example above is more relevant, because what I am ultimately aiming for is to not need to make member functions const, and yet be able to call them for const class instances.