4 ms·
echo "scale=2; $SECONDS / 60 / 60" | bc # will give 2 digits after the decimal point, instead of bc -l which gives more digits of precision after the decimal p
by vram22 9y ago
echo "scale=2; $SECONDS / 60 / 60" | bc
# will give 2 digits after the decimal point, instead of bc -l which gives more digits of precision after the decimal point, than we may usually want for this particular calculation.
- lozf 9y agoRecently I needed results that included nothing after the decimal point, so resorted to awk to do the math: awk "BEGIN { print int($SECONDS /60 /60)}"
- vram22 9y agoInteresting. I suppose you had to type Ctrl-D or Ctrl-Z to signal no input to awk, since it expects some in the above command? Never tried running awk without either a filename as input or stdin coming from a file or a pipe. Will check it and see what happens. Modifying my example from above: echo "scale=0; $SECONDS / 60 / 60" | bc might also work, need to check.
- otherflavors 9y agoprintf "%s 60 60 *2k/p" "$SECONDS" | dc