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Easy. If it is a bot - don't charge. Probably a few lines of code. if ( is_bot() } { charge = 0 }. Also, be transparent: you could even show a report of how
by ransom1538 9y ago
Easy. If it is a bot - don't charge. Probably a few lines of code. if ( is_bot() } { charge = 0 }. Also, be transparent: you could even show a report of how many bots it removed. BUT this would cut their ad revenue to ~0.
- illnewsthat 9y ago> if ( is_bot() } { charge = 0 } That's some funny pseudo code. The assumption being they can write an is_bot function that is reliable.
- oliv__ 9y agoMore like: if (is_bot_probability >= 90%) { charge = 0 }
- deleted 9y ago[deleted]