3 ms·
In your explanation you say that "The SHA256 algorithm will calculate a unique hash, given those inputs.". Obviously, this can't be the case (since the number
by nonidit 9y ago
In your explanation you say that "The SHA256 algorithm will calculate a unique hash, given those inputs.".
Obviously, this can't be the case (since the number of possible hashes is smaller than the number of inputs). It is just very unlikely, that the same hash appears twice.
- lambdaxdotx 9y agothis is quite the nitpick... for all intents and purposes, sha3_256 will _not_ collide; it's infeasible to the point that it can be said that the resulting hash is unique. I mean, of course you are technically right, but sometimes all the details are not worth mentioning when explaining a lot of small parts of a bigger picture.