It's not though, AFAIK the x.foo() syntax is just sugar for let a = Foo; Foo::bar(&a); // if bar takes &self Plus, there is no concept of inheritance. I don't

It's not though, AFAIK the x.foo() syntax is just sugar for let a = Foo; Foo::bar(&a); // if bar takes &self Plus, there is no concept of inheritance. I don't see how that meets any definition of OOP unless you make the definition so weak as to be meaningless.