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How does he deal with the diagonal of the square? because that needs sqrt(2).
by rocqua 9y ago
How does he deal with the diagonal of the square? because that needs sqrt(2).
- jacobolus 9y agoHe bases his metrical geometry on “quadrance” (squared distance) and “spread” (squared sine) rather than distance and angle measure.
- gus_massa 9y agoThen, how does he deal with the the pentagon? because that needs sqrt(5+sqrt(5)) or something similar with two nested square roots.
- jacobolus 9y agoTo deal with pentagons you need to extend the field of rationals by an additional element. Wildberger is kind of ambivalent about finite field extensions.