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It doesn't seem to say anything like that. Looking at it again, I see this: > It is also worth mentioning that increasing the bit depth of the audio representa
by Veratyr 9y ago
It doesn't seem to say anything like that. Looking at it again, I see this:
> It is also worth mentioning that increasing the bit depth of the audio representation from 16 to 24 bits does not increase the perceptible resolution or 'fineness' of the audio. It only increases the dynamic range, the range between the softest possible and the loudest possible sound, by lowering the noise floor. However, a 16-bit noise floor is already below what we can hear.
But I don't understand, why is this? Is the step in volume between two values fixed regardless of the bit depth? If so, why?
- lgunsch 9y agoThe video linked in the top-most comment will beautifully answer your questions. It's also on YouTube. You can think of it as in the sampling rate provides a mathimatical solution to the waveform - it's simply 100% accurate all the time. The bit depth adds extra "buckets" to divide the volumes into . If you have 2 bits, you then have volume levels 0, 1, 2, 3.