4 ms·
False. The I-expression: lambda (x y) display x + x y corresponds to the S-expression: (lambda (x y) (display x) (+ x y))
by rntz 16y ago
False. The I-expression:
lambda (x y)
display x
+ x y
corresponds to the S-expression:
(lambda (x y)
(display x)
(+ x y))