5 ms·
I think you are misreading that. The increase of 10-30 percent is in torque, not MPG.
by IgorPartola 9y ago
I think you are misreading that. The increase of 10-30 percent is in torque, not MPG.
- Danihan 9y agoGah, you're right, thanks. Edited.
- ddeck 9y agoThis is correct, but they're are also predicting an equivalent improvement in fuel consumption: "Compared to the current lineup of SkyActiv-G engines, the SkyActiv-X line should use between 20 and 30 percent less fuel." http://newatlas.com/mazda-skyactiv-x-compression-ignition/50803/ http://newatlas.com/mazda-skyactiv-x-compression-ignition/50...
- flamedoge 9y agomore torque = less rpm @ same hp?
- toxik 9y agoTorque is directly proportional to power, related by angular velocity. So τ Nm of torque at angular velocity ω rad/s will give you power P = τ·ω in watts. In fact this works for three-dimensional τ and ω if · is the scalar product. Oh and an RPM of N is equivalent to angular velocity ω = N·π/30.