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In the proposal, '$class' is actually the proposed keyword for introducing a metaclass; you won't continue to use '$' for all of the classes created from that m
by scott_s 9y ago
In the proposal, '$class' is actually the proposed keyword for introducing a metaclass; you won't continue to use '$' for all of the classes created from that metaclass. stephen82 is suggesting that we use the keyword 'metaclass' instead, which I probably prefer.