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Not sure what you mean exactly, but $class is just an example, you can also have $interface $sometypeofstruct $unmutablevaluetype etc so prefixing that all with
by stinos 9y ago
Not sure what you mean exactly, but $class is just an example, you can also have $interface $sometypeofstruct $unmutablevaluetype etc so prefixing that all with 'meta' would be a mess
- scott_s 9y agoIn the proposal, '$class' is actually the proposed keyword for introducing a metaclass; you won't continue to use '$' for all of the classes created from that metaclass. stephen82 is suggesting that we use the keyword 'metaclass' instead, which I probably prefer.