Speaking of divisors, there are infinite numbers n such that n and n+1 have the same number of divisors. AFAIK we do not have a way to find such an n > N for an

Speaking of divisors, there are infinite numbers n such that n and n+1 have the same number of divisors. AFAIK we do not have a way to find such an n > N for any given N without calculating an infinitely growing sequence.