8 ms·
And 22/7 should be pi day, not 3/14
by emmelaich 9y ago
And 22/7 should be pi day, not 3/14
- aetherson 9y agoAre there 22 months in your year or 14? (That is: It seems weird to express one date as month-last and the other as month-first.)
- gpawl 9y agoParent poster was rejecting the month-first version.
- aetherson 9y agoThen why didn't he write it as 14/3? Anyhow, I thought he was more narrowly saying that 22/7 is closer to the true value of pi than 3.14 is.
- nl 9y agoBecause 3.14 is the approximation of Pi. And yes, that is the reasoning.
- vacri 9y agomonth-first or month-last doesn't matter, until you add more time periods. YY/MM/DD and DD/MM/YY are both fine, but MM/DD/YY is braindead. Month-first gains the edge, though, when you add time-of-day, since no-one does ss/mm/hh
- jkingsbery 9y agoThat's known as "Pi Approximation Day" - http://www.qwantz.com/index.php?comic=955 http://www.qwantz.com/index.php?comic=955
- milesvp 9y agoActually PI day should be 6/28. It makes a lot of important formulas simpler... makes me sad we still teach PI, when TAU is mostly superior :P
- dnautics 9y agopi is superior in this respect: If you plug tau into euler's magic formula (e^(tau * i) == 1) it's mostly confusing, but if you plug pi in, (e ^ (pi * i) == -1), it's profound.
- posterboy 9y agoMaybe you developed intuition for one but not the other. It's not at all obvious what kind of difference you perceived.
- dnautics 9y agoThe first case is trivially solvable if tau == 0, or alternatively gives little insight into how imaginary exponents work because 1 is positive. A negative result of the exponentiation function is glaringly unusual, and provokes one to question "what exactly is going on here?", Without being unnecessarily complex (as is the case for nonmultiples of pi)
- posterboy 9y agobut to explain the importance of pi because of complex numbers is still not obvious, it seems to hinge on the imaginary number, which to be honest I know next to nothing about so I don't see the connection.
- dTal 9y agoThat's arguable. That the equation is satisfied by both tau and zero hints that complex exponentiation is periodic. I strongly feel that mathematicians prefer the more complex form because it seems mysterious and mystical, which is fun for them but less pedagogically useful.