3 ms·
mass = 4/3 pi radius cubed The cube of a normal distribution is indeterminate. Had the relationship between the mass and the radius been linear (M = a * R + b
by curiousgal 9y ago
mass = 4/3 pi radius cubed
The cube of a normal distribution is indeterminate.
Had the relationship between the mass and the radius been linear (M = a * R + b) then yes the mass would have followed a normal distribution as well (with different parameters of course).
- schoen 9y agoThat factor should be 4/3 rather than 3/4. When you differentiate it, you need to get 4πr² for the surface area.
- curiousgal 9y agoYou are correct, my memory failed me and I didn't check. Thank you.
- user5994461 9y agoThat distribution still has the same median, with half the samples on one side and the other half on the other side. That looks a lot like a normal distribution even if it's not one.