5 ms·
If I read the announcement correctly, the hash is computed on the last value and is distributed separately. Either I miss something or they can change ANY value
by friendzis 9y ago
If I read the announcement correctly, the hash is computed on the last value and is distributed separately. Either I miss something or they can change ANY value in the chain and the last hash would still check out.
It is only viable to use this while constantly querying /last. If network/power/etc. outage lasts more than 60 secs, chains should be considered separate.
Or maybe I'm missing something obvious
- scrumper 9y agoI read "Each... value includes the hash of the previous value... chaining the sequence of values together" which is how immutability is ensured. (Amending a prior value would invalidate the hashes of every subsequent value.)