3 ms·
Wouldn't the weak point in that system then be the PRNG? If so, doesn't that require the use of a crytographically secure PRNG in the first place?
by grosscol 9y ago
Wouldn't the weak point in that system then be the PRNG? If so, doesn't that require the use of a crytographically secure PRNG in the first place?
- smoyer 9y agoYes ... the PRNG is the weak point (just as it always is). And if you're only using enough bits from the PRNG to generate a timestamp, you also have to worry about whether the distribution is flat.