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The Mill isn't an “out-of-order” machine because it's not taking linear code and scheduling it to run out-of-order dynamically (i.e. when it executes). Instead,
by TazeTSchnitzel 9y ago
The Mill isn't an “out-of-order” machine because it's not taking linear code and scheduling it to run out-of-order dynamically (i.e. when it executes). Instead, the compiler does the scheduling.