Sure, but I think most people believe that cos(x)+isin(x)=e^ix because that's how it is defined, in which case e^(i\pi)=-1 isn't even a result. It is at least t

Sure, but I think most people believe that cos(x)+isin(x)=e^ix because that's how it is defined, in which case e^(i\pi)=-1 isn't even a result. It is at least the tiniest bit more interesting than that.