3 ms·
It's not about feeling superior - it's more about correcting people being Wrong on the Internet! > A mile of diameter weights 7 * 10^8 * density_of_the_asteroi
by barrkel 9y ago
It's not about feeling superior - it's more about correcting people being Wrong on the Internet!
> A mile of diameter weights 7 * 10^8 * density_of_the_asteroid kilograms
This sentence, in so far as it can be understood in English, makes a wrong assertion. Only the first mile of diameter approximates to that; "the" mile, not "a" mile. In the context of the conversation - long lost in this subthread - it's the wrong answer without further clarification. It was in reply to the question "How much does a mile weigh?" - again, note "a", not any specific mile. Someone who takes the reply as an answer to that question would be even more misled, irrespective of how well rimliu understands the problem.
To be really specific: I think 90+% of people would think that an asteroid with a diameter of two miles would weigh 14e8 * density, given this answer - and they'd be wrong, and increasingly wrong the larger and larger an asteroid they're calculating for. Because mathematical intuition is not common.
I added the clarification. Then you came in with your intervention, for reasons that aren't yet clear to me.
- Retric 9y ago'I think 90+% of people would think that an asteroid with a diameter of two miles would weigh 14e8 * density' If this where YouTube then you might be right, but I would assume the vast majority of people here understand the r^3 part of the formula for a sphere especially when it was included in the same comment. Though they may forget about the 4/3. And again, it's perfectly valid English to say a mile when you mean exactly 1 mile. AKA "> How much does a mile weigh?" replace that with "How many feet are in a mile." and someone saying 5280 is being reasonable by answering the question. PS: Now if the original question was per mile then I would agree with you.