2 ms·
How about the .-operator while ((calls.moveToNext)() && (count < howMany)) { or while ((calls.moveToNext()) && (count < howMany)) {
by jonsen 16y ago
How about the .-operator
while ((calls.moveToNext)() && (count < howMany)) {
or
while ((calls.moveToNext()) && (count < howMany)) {
- barrkel 16y agoJava does not, as yet, have a kind of method or closure reference type, so this ambiguity doesn't exist - the parentheses on the method call are not an operator like in C++.