3 ms·
There's a section about that: http://tauday.com/#sec:euler_s_formula http://tauday.com/#sec:euler_s_formula e^(tau * i) = 1 e^(pi * i) = -1 Which loo
by JeremyBanks 16y ago
There's a section about that: http://tauday.com/#sec:euler_s_formula http://tauday.com/#sec:euler_s_formula
e^(tau * i) = 1
e^(pi * i) = -1
Which looks better?