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The shaking represents any sort of action that doesn't perform a measurement. It was the first thing I thought of that could affect the ball without opening the
by lucozade 9y ago
The shaking represents any sort of action that doesn't perform a measurement. It was the first thing I thought of that could affect the ball without opening the box.
It could be that the shaking didn't have an effect. But equally, it could have had an effect. The spooky bit is that the other ball 'knows' whether it did or not in a non-local way.
- darkerside 9y agoBut isn't it possible that performing "shaking" might not affect any "ball" when it's "inside of a box"?