3 ms·
The implication in the article is that humans will be doing this on the fly. This solution does not fit with that criterion.
by failrate 9y ago
The implication in the article is that humans will be doing this on the fly. This solution does not fit with that criterion.
- tzs 9y agoThat's an easy algorithm to do on the fly. Take two d6s that can be distinguished (different color, for example). Call them A and B. Roll A and B. If A is a 6, reroll A until it is not 6. If B is even, take A as your result. If B is odd, take A+5 as your result. (I changed to use B odd/even instead of B <= 3 because that might be easier for people). That gives you a number from 1 to 10. Subtract 1 if you need 0 to 9. If your two d6s cannot be distinguished, take the one that lands leftmost to be A.
- failrate 9y agoNo. I won't do any of that. Most games already have enough essential complexity that all of its components must be able to be interpreted at a glance. D20s and D10s make this easy and intuitive without requiring an algorithm or mathematical post-process.