3 ms·
There's also the pattern that every prime (above 3) modulo 6 is congruent to 1 or 5. I suspect that some of the pattern comes from that fact.
by paulgb 16y ago
There's also the pattern that every prime (above 3) modulo 6 is congruent to 1 or 5. I suspect that some of the pattern comes from that fact.
- nitrogen 16y agoIs there a more generalized version of that pattern, perhaps something like this (I haven't checked): let P(n) be the nth prime number: P(1)=2, etc. let n be an integer >= 2, and m be an integer > n then P(m) ≡ 1 and (P(n) - 1) (mod P(n)) ?