3 ms·
No, that's not right. Cantor's argument says that it's impossible to create a bijection between the rationals and the irrationals. It does this by considering
by jfarmer 16y ago
No, that's not right. Cantor's argument says that it's
impossible to create a bijection between the rationals and the irrationals. It does this by considering an arbitrary bijection and then showing there is at
least one irrational not in that bijections
image (a contradiction).
In that sense there are "more" irrationals than rationals.
There is another field of mathematics called measure
theory in which the notion of "almost all" is made precise and in that case, yes, almost all reals are irrational. But that has nothing to do with Cantor's proof, which is pure set theory.