You got it backwards. The Java snippet will print "Lassie". In Java, object names are references to objects, and passing them to functions copies the references

You got it backwards. The Java snippet will print "Lassie". In Java, object names are references to objects, and passing them to functions copies the references, so of course modifying the formal parameter (d from replaceDogWithToby()) doesn't modify the actual parameter (d from main()).