3 ms·
Given Tao's rotating frame: * For each M-mass, the centrifugal-vector lies along the x-axis. * For each m-mass, the centrifugal-vector lies along the z-axis.
by Double_Cast 9y ago
Given Tao's rotating frame:
* For each M-mass, the centrifugal-vector lies along the x-axis.
* For each m-mass, the centrifugal-vector lies along the z-axis.
* For each centrifugal-vector, the magnitude is proportional to "the point-mass's distance from the disk's axis-of-rotation (the y-axis)". Since the m-masses move along a unit circle in the yz-plane, their magnitudes vary.
E.g. an m-mass which starts at (0, .9, .1) will accelerate towards (0, 0, 1) then deccelerate towards (0, -.9, .1). Then it will retrace its path. This results in oscillation between (0, .9, .1) and (0, -.9, .1) along a semi-circle in the yz-plane.
N.b. no oscillation will occur if an m-mass starts at exactly (0, 1, 0).