3 ms·
The code uses dividers[divisor] so dividers[3](6, 3) so undefined(6,3) and that does not work
by rndgermandude 10y ago
The code uses dividers[divisor] so dividers[3](6, 3) so undefined(6,3) and that does not work
- idbehold 10y agoOh, yeah the divideSomeNumbers() function doesn't work correctly. It should probably be using: var divider = dividers[divisor] || dividers[undefined];