4 ms·
Why is that so ? If you can do a<b and a>b reliably, you can get equality as !(a<b || b<a). Inequality has the same issues for very close values.
by bubblethink 10y ago
Why is that so ? If you can do a<b and a>b reliably, you can get equality as !(a<b || b<a). Inequality has the same issues for very close values.
- greglindahl 10y agoTry putting NaN into your equation: not equal to itself.
- deleted 10y ago[deleted]