3 ms·
How about instead of average comment score, you consider average likelihood of quality, treating the score (or its log) as odds? That is, w=avg(score/(1+score))
by sesqu 16y ago
How about instead of average comment score, you consider average likelihood of quality, treating the score (or its log) as odds? That is, w=avg(score/(1+score)). That way a single popular comment won't dominate.
- riffer 16y agoIt appears he throws out the highest rated comment when computing the average. I assume that's because of what you're getting at: the distribution of comment scores tend to look like a power law, so the arithmetic mean of all the scores isn't really the right number to use.
- SandB0x 16y agoOr just take the median.