3 ms·
A near optimal one is f2(x) = 5 :)
by amadvance 10y ago
A near optimal one is f2(x) = 5
:)
- _Codemonkeyism 10y agoMost efficient is f2(x)=2 or f1(x)=1 I think, not sure yet :-)
- passiveincomelg 10y agoI'd say 2 because code reviews are one of the rare "methodologies" that improve quality in my experience.