3 ms·
You can't avoid it. The java.lang.Class getTypeParameters() method will give you back the same instance. System.out.println(System.identityHashCode(java.ut
by benmmurphy 10y ago
You can't avoid it. The java.lang.Class getTypeParameters() method will give you back the same instance.
System.out.println(System.identityHashCode(java.util.List.class.getTypeParameters()[0]));
System.out.println(System.identityHashCode(java.util.List.class.getTypeParameters()[0]));
2018699554
2018699554