2 ms·
> L_n = L_{n-1} + L_n L_{n-1} = 0 ;-) You probably meant L_n = L_{n-2} + L_n{n-1}
by zeeZ 10y ago
> L_n = L_{n-1} + L_n
L_{n-1} = 0 ;-)
You probably meant L_n = L_{n-2} + L_n{n-1}
- Sniffnoy 10y agoThanks! This is what happens when you decide to switch indices, I guess. Unfortunately seems I can no longer edit the comment.