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If you had a normal electrochemical cell, with a sodium anode and sulfur cathode, and liquid electrolyte, the sodium would release an electron into the circuit
by logfromblammo 10y ago
If you had a normal electrochemical cell, with a sodium anode and sulfur cathode, and liquid electrolyte, the sodium would release an electron into the circuit and hop off the solid anode into the liquid electrolyte. On the other side, sulfur would grab electrons from the circuit and hop off the solid cathode into the liquid electrolyte.
In the middle, the ions would keep their charges and physically arrange themselves such that the charges are balanced in every direction. This would be an energy minimum, and it would be hard to reverse. Trying would probably cause the electrolyte to decompose instead of redepositing the original reactants onto their electrodes. It would not be rechargeable.
As a physical metaphor, you have two mutually-attracted boulders rolling down from opposite ridges into the same bowl-shaped energy valley. When they collide, they strike with such force they turn to sand.
In the rechargeable battery, you prevent that last step by putting a giant springy foam block in the center of the valley, so that the boulders can't touch. You prevent the sodium and sulfur from coordinating physically to cancel out the physical force from separated charges. Then to recharge, you tow or push the boulders back up the hill.
I think the "same metal at the cathode" might be an artifact of putting the springy foam block in to keep the boulders intact. You couldn't switch the anode and the cathode any more easily than you could swap the elevations of the ridges and the valley. That is, it takes as much energy to do the physical rearrangement as it would to charge the system electrically.
- hwillis 10y ago>I think the "same metal at the cathode" might be an artifact of putting the springy foam block in to keep the boulders intact. You couldn't switch the anode and the cathode any more easily than you could swap the elevations of the ridges and the valley. That is, it takes as much energy to do the physical rearrangement as it would to charge the system electrically. That is the case in normal batteries, but in this battery the start and end product are both just lithium metal- not intercalated into graphite or bound to sulfur, literally just solid lithium. There's no (obvious) place for the energy to be hiding. It would appear that you could just scrape it off and receive free energy.
- hwillis 10y agoTo follow your boulder/hill metaphor, the lithium boulder rolls down the hill (crosses the electrolyte), settles at the bottom of the valley (bonds sulfur)... And then somehow as more lithium rolls down the hill, it continues to pile up at the bottom until it forms another hill, the same size as the first (lithium plates onto the anode). That's what they claim happens- that the sulfur acts as a redox center and sets the voltage for an unlimited amount of lithium. But a redox center cannot just lower the voltage of an arbitrary amount of metal. The metal is an entirely normal bond and can be cut with an energy proportional to mass^(2/3), while the energy stored increases linearly.