Only if your version of the 8cc binary doesn't have GCC in it's compiler heritage, which it probably does. The blog actually goes into this a bit, stating that

Only if your version of the 8cc binary doesn't have GCC in it's compiler heritage, which it probably does. The blog actually goes into this a bit, stating that the byte-value of '\n' never occurs in the source-code of 8cc. Instead, that value comes from gcc. It is entirely possible that gcc has the same property, eventually the source could be a hand-written compiler. Really, to get around trusting trust, you need a compiler who's entire lineage you know (up to the hand-written compiler) and trust.