3 ms·

But why is that bad?

• lmitchell 10y ago
  Because `i` isn't an int, it's an initializer_list, and you almost never want to actually create an initializer_list instead of an int? Seems pretty understandable to me.
• thecpphorse 10y ago
  It's unexpected. Nobody ever* wanted to assign an initializer list to a named variable. [*] pretty much