3 ms·
If anyone is curious, the reason is that many/most special relativistic effects are proportional to gamma = 1/sqrt(1-v^2/c^2), with gamma = 1 being non-relativi
by jessriedel 10y ago
If anyone is curious, the reason is that many/most special relativistic effects are proportional to gamma = 1/sqrt(1-v^2/c^2), with gamma = 1 being non-relativistic. Even at v=20% of c, gamma is only 1.02 (a mere 2% effect).
http://www.wolframalpha.com/input/?t=crmtb01&f=ob&i=Plot%5B1%2FSqrt(1-v%5E2),%7Bv,0,1%7D%5D http://www.wolframalpha.com/input/?t=crmtb01&f=ob&i=Plot%5B1...
- cuspycode 10y agoGeneral relativity also accounts for gravitational/accelerational effects, in addition to the speed-related effects. For example, in the Schwarzschild metric[1], effects such as time dilation are on the order of 1-phi/c^2 where phi=GM/r. Or expressed in terms of "g-force": phi=gr. [1] https://en.wikipedia.org/wiki/Schwarzschild_metric https://en.wikipedia.org/wiki/Schwarzschild_metric