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"It's totally possible to make it work, it just isn't terribly simple." Please, it's as simple as a three-component boost converter - one IC and two resistors.
by lightedman 10y ago
"It's totally possible to make it work, it just isn't terribly simple."
Please, it's as simple as a three-component boost converter - one IC and two resistors. Same thing I use to bump 1.2V up to 3.6Vto run LEDs. It takes zero space (7x7mm total.)
- pfooti 10y agowhat's the efficiency of that boost converter? how much energy gets dissipated as heat in that setup, and is that likely to cause a fire?
- thesmok 10y agoModern boost converters have efficiency from 80% to 95%. They also operate at high frequencies – 1MHz or even 3MHz, which allows to make inductors incredibly small. Boost converters aren't a problem for a long time now.
- hwillis 10y agoSure. You could use an SOT23 or a QFN like this: http://www.digikey.com/product-detail/en/texas-instruments/TPS61090RSAR/296-15259-2-ND/566911 http://www.digikey.com/product-detail/en/texas-instruments/T... That's 4 mm x 4 mm (more with passives, but not too bad), and hits a solid 95% efficiency at the normal load of an iphone, and is above 90% all peak loads. Heat dissipation will be fine, all parts cost about $1.20. Low EMI. However, its still a dozen new components. It's a ~10% tradeoff somewhere and while that may be totally worth it, its not simple. Phones do not have square millimeters to spare.
- Arizhel 10y ago>Phones do not have square millimeters to spare. Actually, they do, when you're replacing the battery with one with 3 times the energy density. Use some of the saved space for your DC-DC converter.
- hwillis 10y agoIts like... adding a turbocharger to a car. Yes, it is possible. There are even kits, after a fashion. But it is still not simple. Also, its not even at the stage of a hypothetical question yet. This battery would last about two weeks in an iphone under these load conditions. The only reason it "looks" possible is if you're considering a battery that is not this one.
- dreamcompiler 10y agoIf it's a true boost converter, it's also going to need an inductor somewhere. If it's really just driving an LED, it could be a charge pump, which uses capacitors instead. But charge pumps probably can't handle the current level that a phone requires.
- lightedman 10y ago"If it's a true boost converter, it's also going to need an inductor somewhere." We use resistors as inductors. Plenty of wound resistors in teeny-tiny packages exist, that's how we have metal detectors with credit card-sized boards, the literal bulk of the unit is the frame and coil assembly and board housing + adjustment controls. Older gas charge pumps can handle it, but they're bulky and they are lossy and generate a lot of heat.