3 ms·
"Why does the function declare which parameters are "comptime"? " Because it's at least exponential time and space otherwise, and sometimes much more :) (beca
by DannyBee 10y ago
"Why does the function declare which parameters are "comptime"?
"
Because it's at least exponential time and space otherwise, and sometimes much more :)
(becasue you may have to duplicate the entire call path rooted at foo)