4 ms·
Yes, but you picked two hash functions which are known to be insecure. Their complexity reduction argument appears to apply to cases where you are not using pur
by johncolanduoni 10y ago
Yes, but you picked two hash functions which are known to be insecure. Their complexity reduction argument appears to apply to cases where you are not using pure brute force for either hash, which would be the case if you were attacking MD5 and SHA1.
- hvidgaard 10y agoI did so quite on purpose. Both are concidered broken, but combined, only the bruteforce attack is known to work, i.e. "the whole is greater than the sum of its parts".