3 ms·
I believe there is a way to do it so that the MD5 collision would only be 2^64. This is also how MD5 collisions can be created without any special techniques, m
by yuhong 10y ago
I believe there is a way to do it so that the MD5 collision would only be 2^64. This is also how MD5 collisions can be created without any special techniques, meaning that MD5 was always only barely more secure than 56-bit DES for example.