4 ms·
This would still be just an average, right? Isn't it 0$ to $2.8M depending on luck?
by bbarn 10y ago
This would still be just an average, right? Isn't it 0$ to $2.8M depending on luck?
- Aissen 10y agoI don't think that's how averages work. But it's true that relying on the birthday paradox, you can reduce the average. I was just trying to compute the "cloud" cost of 110 GPUs for 1 year (or the equivalent for a day, assuming this is embarrassingly parallel).