2 ms·
You're right! My scheme is rusty I guess. I should have said: (x . (y . (z . NIL))) <=> ['x', 'y', 'z']
by bijection 10y ago
You're right! My scheme is rusty I guess.
I should have said:
(x . (y . (z . NIL))) <=> ['x', 'y', 'z']
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