3 ms·
No, my point is not that it cannot be done (both Rust and C++ are Turing-complete, so "cannot be done" does not make sense for anything that's a computable prop
by rbehrends 10y ago
No, my point is not that it cannot be done (both Rust and C++ are Turing-complete, so "cannot be done" does not make sense for anything that's a computable property), but that it comes with a cost. See my other response for the details.