3 ms·
Because the type of a JSON object's fields is not known at compile-time. let s = parseJson("{'A': 'foo'}") s["A"] # What type is this? We don't know un
by dom96 10y ago
Because the type of a JSON object's fields is not known at compile-time.
let s = parseJson("{'A': 'foo'}")
s["A"] # What type is this? We don't know until we parse the JSON.